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131020043433 = 343673347811
BaseRepresentation
bin111101000000101100…
…1110011010010101001
3110112012000022211011020
41322001121303102221
54121312112342213
6140104554123053
712315540664626
oct1720131632251
9415160284136
10131020043433
1150624442934
1221486420489
13c48030bb26
1464acb5334d
15361c6a3923
hex1e816734a9

131020043433 has 4 divisors (see below), whose sum is σ = 174693391248. Its totient is φ = 87346695620.

The previous prime is 131020043431. The next prime is 131020043437. The reversal of 131020043433 is 334340020131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131020043433 - 21 = 131020043431 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131020043431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21836673903 + ... + 21836673908.

It is an arithmetic number, because the mean of its divisors is an integer number (43673347812).

Almost surely, 2131020043433 is an apocalyptic number.

It is an amenable number.

131020043433 is a deficient number, since it is larger than the sum of its proper divisors (43673347815).

131020043433 is an equidigital number, since it uses as much as digits as its factorization.

131020043433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43673347814.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 131020043433 its reverse (334340020131), we get a palindrome (465360063564).

The spelling of 131020043433 in words is "one hundred thirty-one billion, twenty million, forty-three thousand, four hundred thirty-three".

Divisors: 1 3 43673347811 131020043433