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131020140013402 = 265510070006701
BaseRepresentation
bin11101110010100110000000…
…111001110110011101011010
3122011220101212211102101210011
4131302212000321312131122
5114133113221320412102
61142353453230512134
736411615131561653
oct3562460071663532
9564811784371704
10131020140013402
11388243693932a2
12128406b796564a
1358151b923bb03
14244d5a133652a
151023203ed62d7
hex772980e7675a

131020140013402 has 4 divisors (see below), whose sum is σ = 196530210020106. Its totient is φ = 65510070006700.

The previous prime is 131020140013397. The next prime is 131020140013423. The reversal of 131020140013402 is 204310041020131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 78603278490801 + 52416861522601 = 8865849^2 + 7239949^2 .

It is a super-2 number, since 2×1310201400134022 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32755035003349 + ... + 32755035003352.

Almost surely, 2131020140013402 is an apocalyptic number.

131020140013402 is a deficient number, since it is larger than the sum of its proper divisors (65510070006704).

131020140013402 is an equidigital number, since it uses as much as digits as its factorization.

131020140013402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65510070006703.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 131020140013402 its reverse (204310041020131), we get a palindrome (335330181033533).

The spelling of 131020140013402 in words is "one hundred thirty-one trillion, twenty billion, one hundred forty million, thirteen thousand, four hundred two".

Divisors: 1 2 65510070006701 131020140013402