Base | Representation |
---|---|
bin | 11101110010100110000100… |
… | …100011010100000101011011 |
3 | 122011220102001002120201122001 |
4 | 131302212010203110011123 |
5 | 114133113333002324144 |
6 | 1142353503254341431 |
7 | 36411616504020145 |
oct | 3562460443240533 |
9 | 564812032521561 |
10 | 131020201214299 |
11 | 3882439a994451 |
12 | 1284071435a877 |
13 | 58151c8b19567 |
14 | 244d5a9507c95 |
15 | 1023209574bd4 |
hex | 7729848d415b |
131020201214299 has 2 divisors, whose sum is σ = 131020201214300. Its totient is φ = 131020201214298.
The previous prime is 131020201214257. The next prime is 131020201214321. The reversal of 131020201214299 is 992412102020131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131020201214299 - 225 = 131020167659867 is a prime.
It is a super-2 number, since 2×1310202012142992 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131020201211299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510100607149 + 65510100607150.
It is an arithmetic number, because the mean of its divisors is an integer number (65510100607150).
Almost surely, 2131020201214299 is an apocalyptic number.
131020201214299 is a deficient number, since it is larger than the sum of its proper divisors (1).
131020201214299 is an equidigital number, since it uses as much as digits as its factorization.
131020201214299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 37.
The spelling of 131020201214299 in words is "one hundred thirty-one trillion, twenty billion, two hundred one million, two hundred fourteen thousand, two hundred ninety-nine".
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