Base | Representation |
---|---|
bin | 1011111010101000110101… |
… | …1000110001001011000001 |
3 | 1201101112121110112001000220 |
4 | 2332222031120301023001 |
5 | 3204130420204124441 |
6 | 43510552545133253 |
7 | 2521406220206001 |
oct | 276521530611301 |
9 | 51345543461026 |
10 | 13102022333121 |
11 | 41a159a046687 |
12 | 157731492a229 |
13 | 740691461577 |
14 | 3341d98b6001 |
15 | 17ac311e6466 |
hex | bea8d6312c1 |
13102022333121 has 8 divisors (see below), whose sum is σ = 17469391336320. Its totient is φ = 8734667442672.
The previous prime is 13102022333089. The next prime is 13102022333171. The reversal of 13102022333121 is 12133322020131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13102022333121 - 25 = 13102022333089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102022333091 and 13102022333100.
It is not an unprimeable number, because it can be changed into a prime (13102022333171) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1128870 + ... + 5241983.
It is an arithmetic number, because the mean of its divisors is an integer number (2183673917040).
Almost surely, 213102022333121 is an apocalyptic number.
It is an amenable number.
13102022333121 is a deficient number, since it is larger than the sum of its proper divisors (4367369003199).
13102022333121 is an equidigital number, since it uses as much as digits as its factorization.
13102022333121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7056375.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13102022333121 its reverse (12133322020131), we get a palindrome (25235344353252).
The spelling of 13102022333121 in words is "thirteen trillion, one hundred two billion, twenty-two million, three hundred thirty-three thousand, one hundred twenty-one".
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