Base | Representation |
---|---|
bin | 11101110010100110000110… |
… | …010001111101110011010011 |
3 | 122011220102010010011102100201 |
4 | 131302212012101331303103 |
5 | 114133113412414033021 |
6 | 1142353510212200031 |
7 | 36411620305410625 |
oct | 3562460621756323 |
9 | 564812103142321 |
10 | 131020230221011 |
11 | 388244052a663a |
12 | 12840722009017 |
13 | 5815201b343b1 |
14 | 244d5ad2d8c15 |
15 | 102320bda4591 |
hex | 77298647dcd3 |
131020230221011 has 2 divisors, whose sum is σ = 131020230221012. Its totient is φ = 131020230221010.
The previous prime is 131020230220991. The next prime is 131020230221047. The reversal of 131020230221011 is 110122032020131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131020230221011 - 29 = 131020230220499 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131020230221011.
It is not a weakly prime, because it can be changed into another prime (131020230221051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510115110505 + 65510115110506.
It is an arithmetic number, because the mean of its divisors is an integer number (65510115110506).
Almost surely, 2131020230221011 is an apocalyptic number.
131020230221011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131020230221011 is an equidigital number, since it uses as much as digits as its factorization.
131020230221011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 131020230221011 its reverse (110122032020131), we get a palindrome (241142262241142).
The spelling of 131020230221011 in words is "one hundred thirty-one trillion, twenty billion, two hundred thirty million, two hundred twenty-one thousand, eleven".
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