Base | Representation |
---|---|
bin | 11101110010100110000110… |
… | …111000110101110101100010 |
3 | 122011220102010211100011202211 |
4 | 131302212012320311311202 |
5 | 114133113423021141002 |
6 | 1142353511214432334 |
7 | 36411620461134154 |
oct | 3562460670656542 |
9 | 564812124304684 |
10 | 131020240412002 |
11 | 38824410027247 |
12 | 128407255026aa |
13 | 5815203c91b76 |
14 | 244d5b07ccad4 |
15 | 102320cc18dd7 |
hex | 772986e35d62 |
131020240412002 has 4 divisors (see below), whose sum is σ = 196530360618006. Its totient is φ = 65510120206000.
The previous prime is 131020240411961. The next prime is 131020240412041. The reversal of 131020240412002 is 200214042020131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 87627178961721 + 43393061450281 = 9360939^2 + 6587341^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32755060102999 + ... + 32755060103002.
Almost surely, 2131020240412002 is an apocalyptic number.
131020240412002 is a deficient number, since it is larger than the sum of its proper divisors (65510120206004).
131020240412002 is an equidigital number, since it uses as much as digits as its factorization.
131020240412002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65510120206003.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 131020240412002 its reverse (200214042020131), we get a palindrome (331234282432133).
The spelling of 131020240412002 in words is "one hundred thirty-one trillion, twenty billion, two hundred forty million, four hundred twelve thousand, two".
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