Base | Representation |
---|---|
bin | 1011111010101000111000… |
… | …0001111000111110110010 |
3 | 1201101112122012210201021001 |
4 | 2332222032001320332302 |
5 | 3204130430434104020 |
6 | 43510554012152214 |
7 | 2521406410634152 |
oct | 276521601707662 |
9 | 51345565721231 |
10 | 13102033113010 |
11 | 41a15a5139786 |
12 | 157731846866a |
13 | 7406937670ba |
14 | 3341db0c0762 |
15 | 17ac3212550a |
hex | bea8e078fb2 |
13102033113010 has 16 divisors (see below), whose sum is σ = 23935654524096. Its totient is φ = 5162592151728.
The previous prime is 13102033112999. The next prime is 13102033113019. The reversal of 13102033113010 is 1031133020131.
It is a super-2 number, since 2×131020331130102 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13102033113019) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9777635982 + ... + 9777637321.
It is an arithmetic number, because the mean of its divisors is an integer number (1495978407756).
Almost surely, 213102033113010 is an apocalyptic number.
13102033113010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13102033113010 is a deficient number, since it is larger than the sum of its proper divisors (10833621411086).
13102033113010 is a wasteful number, since it uses less digits than its factorization.
13102033113010 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19555273377.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13102033113010 its reverse (1031133020131), we get a palindrome (14133166133141).
The spelling of 13102033113010 in words is "thirteen trillion, one hundred two billion, thirty-three million, one hundred thirteen thousand, ten".
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