1310204041 has 2 divisors, whose sum is σ = 1310204042. Its totient is φ = 1310204040.

The previous prime is 1310203987. The next prime is 1310204047. The reversal of 1310204041 is 1404020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 770617600 + 539586441 = 27760^2 + 23229^2 .

It is an emirp because it is prime and its reverse (1404020131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310204041 - 2¹¹ = 1310201993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1310204047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655102020 + 655102021.

It is an arithmetic number, because the mean of its divisors is an integer number (655102021).

Almost surely, 2^1310204041 is an apocalyptic number.

It is an amenable number.

1310204041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310204041 is an equidigital number, since it uses as much as digits as its factorization.

1310204041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 1310204041 is about 36196.7407510676. The cubic root of 1310204041 is about 1094.2409871763.

Adding to 1310204041 its reverse (1404020131), we get a palindrome (2714224172).

The spelling of 1310204041 in words is "one billion, three hundred ten million, two hundred four thousand, forty-one".