Base | Representation |
---|---|
bin | 10011000100001110100… |
… | …110101010000011101100 |
3 | 11122020212210100020010102 |
4 | 103010032212222003230 |
5 | 132431302232240134 |
6 | 2441522512130232 |
7 | 163442140405103 |
oct | 23041646520354 |
9 | 4566783306112 |
10 | 1310210040044 |
11 | 465725457414 |
12 | 191b16836978 |
13 | 96724475a59 |
14 | 475b358503a |
15 | 2413547237e |
hex | 1310e9aa0ec |
1310210040044 has 12 divisors (see below), whose sum is σ = 2327089474584. Its totient is φ = 645327333024.
The previous prime is 1310210040023. The next prime is 1310210040047. The reversal of 1310210040044 is 4400400120131.
It is a super-3 number, since 3×13102100400443 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1310210039998 and 1310210040025.
It is not an unprimeable number, because it can be changed into a prime (1310210040047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2444421449 + ... + 2444421984.
It is an arithmetic number, because the mean of its divisors is an integer number (193924122882).
Almost surely, 21310210040044 is an apocalyptic number.
It is an amenable number.
1310210040044 is a deficient number, since it is larger than the sum of its proper divisors (1016879434540).
1310210040044 is a wasteful number, since it uses less digits than its factorization.
1310210040044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4888843504 (or 4888843502 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1310210040044 its reverse (4400400120131), we get a palindrome (5710610160175).
The spelling of 1310210040044 in words is "one trillion, three hundred ten billion, two hundred ten million, forty thousand, forty-four".
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