Base | Representation |
---|---|
bin | 1011111010101001001000… |
… | …1000101110010101001001 |
3 | 1201101112211000110012122001 |
4 | 2332222102020232111021 |
5 | 3204131101103411012 |
6 | 43511004513031001 |
7 | 2521411205400415 |
oct | 276522210562511 |
9 | 51345730405561 |
10 | 13102102013257 |
11 | 41a1630019534 |
12 | 1577337555461 |
13 | 7406a4b0c18a |
14 | 3342062d7d45 |
15 | 17ac381d5357 |
hex | bea9222e549 |
13102102013257 has 2 divisors, whose sum is σ = 13102102013258. Its totient is φ = 13102102013256.
The previous prime is 13102102013219. The next prime is 13102102013309. The reversal of 13102102013257 is 75231020120131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13084866524601 + 17235488656 = 3617301^2 + 131284^2 .
It is a cyclic number.
It is not a de Polignac number, because 13102102013257 - 243 = 4306008991049 is a prime.
It is not a weakly prime, because it can be changed into another prime (13102102013857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551051006628 + 6551051006629.
It is an arithmetic number, because the mean of its divisors is an integer number (6551051006629).
Almost surely, 213102102013257 is an apocalyptic number.
It is an amenable number.
13102102013257 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102102013257 is an equidigital number, since it uses as much as digits as its factorization.
13102102013257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520, while the sum is 28.
Adding to 13102102013257 its reverse (75231020120131), we get a palindrome (88333122133388).
The spelling of 13102102013257 in words is "thirteen trillion, one hundred two billion, one hundred two million, thirteen thousand, two hundred fifty-seven".
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