Base | Representation |
---|---|
bin | 11101110010100111000000… |
… | …101111111001000011010011 |
3 | 122011220111122110221111021201 |
4 | 131302213000233321003103 |
5 | 114133122420023110103 |
6 | 1142354151412532031 |
7 | 36411653516206606 |
oct | 3562470057710323 |
9 | 564814573844251 |
10 | 131021211144403 |
11 | 38824868a7a928 |
12 | 12840956621017 |
13 | 581532a122538 |
14 | 244d6636bc33d |
15 | 102326806851d |
hex | 7729c0bf90d3 |
131021211144403 has 2 divisors, whose sum is σ = 131021211144404. Its totient is φ = 131021211144402.
The previous prime is 131021211144377. The next prime is 131021211144419. The reversal of 131021211144403 is 304441112120131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131021211144403 is a prime.
It is not a weakly prime, because it can be changed into another prime (131021211144443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510605572201 + 65510605572202.
It is an arithmetic number, because the mean of its divisors is an integer number (65510605572202).
Almost surely, 2131021211144403 is an apocalyptic number.
131021211144403 is a deficient number, since it is larger than the sum of its proper divisors (1).
131021211144403 is an equidigital number, since it uses as much as digits as its factorization.
131021211144403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 131021211144403 its reverse (304441112120131), we get a palindrome (435462323264534).
The spelling of 131021211144403 in words is "one hundred thirty-one trillion, twenty-one billion, two hundred eleven million, one hundred forty-four thousand, four hundred three".
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