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131021223221443 = 665711968142633
BaseRepresentation
bin11101110010100111000001…
…011101111101100011000011
3122011220111200022200001212111
4131302213001131331203003
5114133122431121041233
61142354152523440151
736411654023646622
oct3562470135754303
9564814608601774
10131021223221443
1138824874879555
121284095a686057
13581532c790609
14244d6651436b9
151023269151acd
hex7729c177d8c3

131021223221443 has 4 divisors (see below), whose sum is σ = 131023191430648. Its totient is φ = 131019255012240.

The previous prime is 131021223221417. The next prime is 131021223221453. The reversal of 131021223221443 is 344122322120131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131021223221443 - 229 = 131020686350531 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131021223221453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 984004746 + ... + 984137887.

It is an arithmetic number, because the mean of its divisors is an integer number (32755797857662).

Almost surely, 2131021223221443 is an apocalyptic number.

131021223221443 is a deficient number, since it is larger than the sum of its proper divisors (1968209205).

131021223221443 is an equidigital number, since it uses as much as digits as its factorization.

131021223221443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1968209204.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 131021223221443 its reverse (344122322120131), we get a palindrome (475143545341574).

The spelling of 131021223221443 in words is "one hundred thirty-one trillion, twenty-one billion, two hundred twenty-three million, two hundred twenty-one thousand, four hundred forty-three".

Divisors: 1 66571 1968142633 131021223221443