131021231224931 has 2 divisors, whose sum is σ = 131021231224932. Its totient is φ = 131021231224930.

The previous prime is 131021231224909. The next prime is 131021231224969. The reversal of 131021231224931 is 139422132120131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131021231224931 is a prime.

It is a super-2 number, since 2×131021231224931² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131021231224891 and 131021231224900.

It is not a weakly prime, because it can be changed into another prime (131021231224991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510615612465 + 65510615612466.

It is an arithmetic number, because the mean of its divisors is an integer number (65510615612466).

Almost surely, 2^{131021231224931} is an apocalyptic number.

131021231224931 is a deficient number, since it is larger than the sum of its proper divisors (1).

131021231224931 is an equidigital number, since it uses as much as digits as its factorization.

131021231224931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 131021231224931 in words is "one hundred thirty-one trillion, twenty-one billion, two hundred thirty-one million, two hundred twenty-four thousand, nine hundred thirty-one".