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1310213130113 is a prime number
BaseRepresentation
bin10011000100001110110…
…010011100011110000001
311122020220000011012220102
4103010032302130132001
5132431304030130423
62441523102252145
7163442205565046
oct23041662343601
94566800135812
101310213130113
11465727177a98
12191b17887055
1396724cb83b4
14475b3b4b1cd
1524135882c28
hex1310ec9c781

1310213130113 has 2 divisors, whose sum is σ = 1310213130114. Its totient is φ = 1310213130112.

The previous prime is 1310213129969. The next prime is 1310213130137. The reversal of 1310213130113 is 3110313120131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1176591445264 + 133621684849 = 1084708^2 + 365543^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310213130113 - 222 = 1310208935809 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1310213130313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655106565056 + 655106565057.

It is an arithmetic number, because the mean of its divisors is an integer number (655106565057).

Almost surely, 21310213130113 is an apocalyptic number.

It is an amenable number.

1310213130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310213130113 is an equidigital number, since it uses as much as digits as its factorization.

1310213130113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1310213130113 its reverse (3110313120131), we get a palindrome (4420526250244).

The spelling of 1310213130113 in words is "one trillion, three hundred ten billion, two hundred thirteen million, one hundred thirty thousand, one hundred thirteen".