Base | Representation |
---|---|
bin | 10011000100001110110… |
… | …110100111010011001011 |
3 | 11122020220002012202010121 |
4 | 103010032312213103023 |
5 | 132431304320114201 |
6 | 2441523141524111 |
7 | 163442221066336 |
oct | 23041666472313 |
9 | 4566802182117 |
10 | 1310214223051 |
11 | 465727854148 |
12 | 191b18113637 |
13 | 967252ab9c6 |
14 | 475b3d5361d |
15 | 241359eb9a1 |
hex | 1310eda74cb |
1310214223051 has 2 divisors, whose sum is σ = 1310214223052. Its totient is φ = 1310214223050.
The previous prime is 1310214223013. The next prime is 1310214223223. The reversal of 1310214223051 is 1503224120131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310214223051 - 221 = 1310212125899 is a prime.
It is a super-2 number, since 2×13102142230512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310214023051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655107111525 + 655107111526.
It is an arithmetic number, because the mean of its divisors is an integer number (655107111526).
Almost surely, 21310214223051 is an apocalyptic number.
1310214223051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310214223051 is an equidigital number, since it uses as much as digits as its factorization.
1310214223051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1310214223051 its reverse (1503224120131), we get a palindrome (2813438343182).
The spelling of 1310214223051 in words is "one trillion, three hundred ten billion, two hundred fourteen million, two hundred twenty-three thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •