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131022000001 = 285745859993
BaseRepresentation
bin111101000000110000…
…1010000111110000001
3110112012011000020001201
41322001201100332001
54121313113000001
6140105104101201
712315563424124
oct1720141207601
9415164006051
10131022000001
1150625559932
1221487004801
13c480845569
1464ad1023bb
15361c93d501
hex1e81850f81

131022000001 has 4 divisors (see below), whose sum is σ = 131067862852. Its totient is φ = 130976137152.

The previous prime is 131021999963. The next prime is 131022000019. The reversal of 131022000001 is 100000220131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 119248664976 + 11773335025 = 345324^2 + 108505^2 .

It is a cyclic number.

It is not a de Polignac number, because 131022000001 - 29 = 131021999489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131022000701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22927140 + ... + 22932853.

It is an arithmetic number, because the mean of its divisors is an integer number (32766965713).

Almost surely, 2131022000001 is an apocalyptic number.

It is an amenable number.

131022000001 is a deficient number, since it is larger than the sum of its proper divisors (45862851).

131022000001 is an equidigital number, since it uses as much as digits as its factorization.

131022000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45862850.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 131022000001 its reverse (100000220131), we get a palindrome (231022220132).

The spelling of 131022000001 in words is "one hundred thirty-one billion, twenty-two million, one", and thus it is an aban number.

Divisors: 1 2857 45859993 131022000001