Base | Representation |
---|---|
bin | 11101110010100111110000… |
… | …100011001100110101011011 |
3 | 122011220120201101000021101012 |
4 | 131302213300203030311123 |
5 | 114133131040324431211 |
6 | 1142354403142044135 |
7 | 36412012425006416 |
oct | 3562476043146533 |
9 | 564816641007335 |
10 | 131022013123931 |
11 | 3882513a742a26 |
12 | 12840b3b11964b |
13 | 5815427319437 |
14 | 244d6dc000b7d |
15 | 10232b3681d8b |
hex | 7729f08ccd5b |
131022013123931 has 2 divisors, whose sum is σ = 131022013123932. Its totient is φ = 131022013123930.
The previous prime is 131022013123927. The next prime is 131022013124071. The reversal of 131022013123931 is 139321310220131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131022013123931 - 22 = 131022013123927 is a prime.
It is a super-3 number, since 3×1310220131239313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (131022013323931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511006561965 + 65511006561966.
It is an arithmetic number, because the mean of its divisors is an integer number (65511006561966).
Almost surely, 2131022013123931 is an apocalyptic number.
131022013123931 is a deficient number, since it is larger than the sum of its proper divisors (1).
131022013123931 is an equidigital number, since it uses as much as digits as its factorization.
131022013123931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 32.
The spelling of 131022013123931 in words is "one hundred thirty-one trillion, twenty-two billion, thirteen million, one hundred twenty-three thousand, nine hundred thirty-one".
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