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131022013123931 is a prime number
BaseRepresentation
bin11101110010100111110000…
…100011001100110101011011
3122011220120201101000021101012
4131302213300203030311123
5114133131040324431211
61142354403142044135
736412012425006416
oct3562476043146533
9564816641007335
10131022013123931
113882513a742a26
1212840b3b11964b
135815427319437
14244d6dc000b7d
1510232b3681d8b
hex7729f08ccd5b

131022013123931 has 2 divisors, whose sum is σ = 131022013123932. Its totient is φ = 131022013123930.

The previous prime is 131022013123927. The next prime is 131022013124071. The reversal of 131022013123931 is 139321310220131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131022013123931 - 22 = 131022013123927 is a prime.

It is a super-3 number, since 3×1310220131239313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (131022013323931) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65511006561965 + 65511006561966.

It is an arithmetic number, because the mean of its divisors is an integer number (65511006561966).

Almost surely, 2131022013123931 is an apocalyptic number.

131022013123931 is a deficient number, since it is larger than the sum of its proper divisors (1).

131022013123931 is an equidigital number, since it uses as much as digits as its factorization.

131022013123931 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 131022013123931 in words is "one hundred thirty-one trillion, twenty-two billion, thirteen million, one hundred twenty-three thousand, nine hundred thirty-one".