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1310221044523 is a prime number
BaseRepresentation
bin10011000100001111010…
…000101000101100101011
311122020220120001022102201
4103010033100220230223
5132431313041411043
62441523544041031
7163442333060116
oct23041720505453
94566816038381
101310221044523
11465730693226
12191b1a463177
1396726829891
14475b4c0b57d
15241363e7c4d
hex1310f428b2b

1310221044523 has 2 divisors, whose sum is σ = 1310221044524. Its totient is φ = 1310221044522.

The previous prime is 1310221044469. The next prime is 1310221044557. The reversal of 1310221044523 is 3254401220131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310221044523 - 237 = 1172782091051 is a prime.

It is a super-2 number, since 2×13102210445232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310221044491 and 1310221044500.

It is not a weakly prime, because it can be changed into another prime (1310221044623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655110522261 + 655110522262.

It is an arithmetic number, because the mean of its divisors is an integer number (655110522262).

Almost surely, 21310221044523 is an apocalyptic number.

1310221044523 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310221044523 is an equidigital number, since it uses as much as digits as its factorization.

1310221044523 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 1310221044523 its reverse (3254401220131), we get a palindrome (4564622264654).

The spelling of 1310221044523 in words is "one trillion, three hundred ten billion, two hundred twenty-one million, forty-four thousand, five hundred twenty-three".