Base | Representation |
---|---|
bin | 1011111010101001100011… |
… | …0001010000100000110011 |
3 | 1201101120002202212021112022 |
4 | 2332222120301100200303 |
5 | 3204131313101133243 |
6 | 43511023530222055 |
7 | 2521414026341345 |
oct | 276523061204063 |
9 | 51346082767468 |
10 | 13102213302323 |
11 | 41a1687920672 |
12 | 157736888492b |
13 | 7406c1ba61b2 |
14 | 334216dc7295 |
15 | 17ac42d69b68 |
hex | bea98c50833 |
13102213302323 has 2 divisors, whose sum is σ = 13102213302324. Its totient is φ = 13102213302322.
The previous prime is 13102213302313. The next prime is 13102213302337. The reversal of 13102213302323 is 32320331220131.
It is a weak prime.
It is an emirp because it is prime and its reverse (32320331220131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13102213302323 - 24 = 13102213302307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13102213302292 and 13102213302301.
It is not a weakly prime, because it can be changed into another prime (13102213302313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551106651161 + 6551106651162.
It is an arithmetic number, because the mean of its divisors is an integer number (6551106651162).
Almost surely, 213102213302323 is an apocalyptic number.
13102213302323 is a deficient number, since it is larger than the sum of its proper divisors (1).
13102213302323 is an equidigital number, since it uses as much as digits as its factorization.
13102213302323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 13102213302323 its reverse (32320331220131), we get a palindrome (45422544522454).
The spelling of 13102213302323 in words is "thirteen trillion, one hundred two billion, two hundred thirteen million, three hundred two thousand, three hundred twenty-three".
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