1310223100001 has 4 divisors (see below), whose sum is σ = 1311996068400. Its totient is φ = 1308450131604.

The previous prime is 1310223099973. The next prime is 1310223100049. The reversal of 1310223100001 is 1000013220131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310223100001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310223100061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 886483091 + ... + 886484568.

It is an arithmetic number, because the mean of its divisors is an integer number (327999017100).

Almost surely, 2^{1310223100001} is an apocalyptic number.

It is an amenable number.

1310223100001 is a deficient number, since it is larger than the sum of its proper divisors (1772968399).

1310223100001 is an equidigital number, since it uses as much as digits as its factorization.

1310223100001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1772968398.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1310223100001 its reverse (1000013220131), we get a palindrome (2310236320132).

The spelling of 1310223100001 in words is "one trillion, three hundred ten billion, two hundred twenty-three million, one hundred thousand, one".