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1310230113 = 3983944389
BaseRepresentation
bin100111000011000…
…1000011001100001
310101022102120211020
41032012020121201
510140404330423
6334002440053
744316525603
oct11606103141
93338376736
101310230113
11612655305
12306963029
1317b5aa4ba
14c6025173
157a0614e3
hex4e188661

1310230113 has 8 divisors (see below), whose sum is σ = 1747190400. Its totient is φ = 873378288.

The previous prime is 1310230099. The next prime is 1310230151. The reversal of 1310230113 is 3110320131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1310230113 - 213 = 1310221921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1310230092 and 1310230101.

It is not an unprimeable number, because it can be changed into a prime (1310230183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7323 + ... + 51711.

It is an arithmetic number, because the mean of its divisors is an integer number (218398800).

Almost surely, 21310230113 is an apocalyptic number.

It is an amenable number.

1310230113 is a deficient number, since it is larger than the sum of its proper divisors (436960287).

1310230113 is an equidigital number, since it uses as much as digits as its factorization.

1310230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54231.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 1310230113 is about 36197.1008921985. The cubic root of 1310230113 is about 1094.2482452982.

Adding to 1310230113 its reverse (3110320131), we get a palindrome (4420550244).

The spelling of 1310230113 in words is "one billion, three hundred ten million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 3 9839 29517 44389 133167 436743371 1310230113