Base | Representation |
---|---|
bin | 111101000000110100… |
… | …0111100101110100011 |
3 | 110112012021210120002021 |
4 | 1322001220330232203 |
5 | 4121314121423433 |
6 | 140105215202311 |
7 | 12315616513423 |
oct | 1720150745643 |
9 | 415167716067 |
10 | 131024014243 |
11 | 506267051a1 |
12 | 21487816397 |
13 | c48109c315 |
14 | 64ad4a8483 |
15 | 361cbda22d |
hex | 1e81a3cba3 |
131024014243 has 4 divisors (see below), whose sum is σ = 131689110960. Its totient is φ = 130358917528.
The previous prime is 131024014229. The next prime is 131024014259. The reversal of 131024014243 is 342410420131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131024014243 - 25 = 131024014211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131024054243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332548063 + ... + 332548456.
It is an arithmetic number, because the mean of its divisors is an integer number (32922277740).
Almost surely, 2131024014243 is an apocalyptic number.
131024014243 is a deficient number, since it is larger than the sum of its proper divisors (665096717).
131024014243 is an equidigital number, since it uses as much as digits as its factorization.
131024014243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 665096716.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 131024014243 its reverse (342410420131), we get a palindrome (473434434374).
The spelling of 131024014243 in words is "one hundred thirty-one billion, twenty-four million, fourteen thousand, two hundred forty-three".
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