Base | Representation |
---|---|
bin | 10011000100010000011… |
… | …110011010101010011011 |
3 | 11122020221222102012220102 |
4 | 103010100132122222123 |
5 | 132431333301344032 |
6 | 2441525553050015 |
7 | 163443001301333 |
oct | 23042036325233 |
9 | 4566858365812 |
10 | 1310241434267 |
11 | 46574114a357 |
12 | 191b2525690b |
13 | 9672ab1850c |
14 | 475b77d80c3 |
15 | 241380c4362 |
hex | 1311079aa9b |
1310241434267 has 2 divisors, whose sum is σ = 1310241434268. Its totient is φ = 1310241434266.
The previous prime is 1310241434213. The next prime is 1310241434363. The reversal of 1310241434267 is 7624341420131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310241434267 - 210 = 1310241433243 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1310241434267.
It is not a weakly prime, because it can be changed into another prime (1310244434267) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655120717133 + 655120717134.
It is an arithmetic number, because the mean of its divisors is an integer number (655120717134).
Almost surely, 21310241434267 is an apocalyptic number.
1310241434267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310241434267 is an equidigital number, since it uses as much as digits as its factorization.
1310241434267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 38.
Adding to 1310241434267 its reverse (7624341420131), we get a palindrome (8934582854398).
The spelling of 1310241434267 in words is "one trillion, three hundred ten billion, two hundred forty-one million, four hundred thirty-four thousand, two hundred sixty-seven".
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