Base | Representation |
---|---|
bin | 10011000100010000101… |
… | …000010111111011110011 |
3 | 11122020222011022211111212 |
4 | 103010100220113323303 |
5 | 132431334433411111 |
6 | 2441530125030335 |
7 | 163443032422412 |
oct | 23042050277363 |
9 | 4566864284455 |
10 | 1310244044531 |
11 | 4657426724a4 |
12 | 191b260b53ab |
13 | 9672b520656 |
14 | 475b7cb7479 |
15 | 2413843c98b |
hex | 13110a17ef3 |
1310244044531 has 2 divisors, whose sum is σ = 1310244044532. Its totient is φ = 1310244044530.
The previous prime is 1310244044521. The next prime is 1310244044569. The reversal of 1310244044531 is 1354404420131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310244044531 - 214 = 1310244028147 is a prime.
It is a super-2 number, since 2×13102440445312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1310244044521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655122022265 + 655122022266.
It is an arithmetic number, because the mean of its divisors is an integer number (655122022266).
Almost surely, 21310244044531 is an apocalyptic number.
1310244044531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310244044531 is an equidigital number, since it uses as much as digits as its factorization.
1310244044531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 1310244044531 its reverse (1354404420131), we get a palindrome (2664648464662).
The spelling of 1310244044531 in words is "one trillion, three hundred ten billion, two hundred forty-four million, forty-four thousand, five hundred thirty-one".
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