Base | Representation |
---|---|
bin | 111101000000110101… |
… | …0100010100101100001 |
3 | 110112012022120202101122 |
4 | 1322001222202211201 |
5 | 4121314223301312 |
6 | 140105232142025 |
7 | 12315623201663 |
oct | 1720152424541 |
9 | 415168522348 |
10 | 131024431457 |
11 | 5062696a6a7 |
12 | 21487997915 |
13 | c4811b71aa |
14 | 64ad576533 |
15 | 361cc6db72 |
hex | 1e81aa2961 |
131024431457 has 2 divisors, whose sum is σ = 131024431458. Its totient is φ = 131024431456.
The previous prime is 131024431441. The next prime is 131024431469. The reversal of 131024431457 is 754134420131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68576420641 + 62448010816 = 261871^2 + 249896^2 .
It is a cyclic number.
It is not a de Polignac number, because 131024431457 - 24 = 131024431441 is a prime.
It is a super-2 number, since 2×1310244314572 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131024431427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65512215728 + 65512215729.
It is an arithmetic number, because the mean of its divisors is an integer number (65512215729).
Almost surely, 2131024431457 is an apocalyptic number.
It is an amenable number.
131024431457 is a deficient number, since it is larger than the sum of its proper divisors (1).
131024431457 is an equidigital number, since it uses as much as digits as its factorization.
131024431457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 35.
Adding to 131024431457 its reverse (754134420131), we get a palindrome (885158851588).
The spelling of 131024431457 in words is "one hundred thirty-one billion, twenty-four million, four hundred thirty-one thousand, four hundred fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •