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131025201331 = 147289889579
BaseRepresentation
bin111101000000110110…
…1011110100010110011
3110112012101000212110111
41322001231132202303
54121314422420311
6140105300442151
712315632556343
oct1720155364263
9415171025414
10131025201331
1150627346062
12214880a9357
13c4813c673b
1464ad6d6d23
15361cd71d21
hex1e81b5e8b3

131025201331 has 4 divisors (see below), whose sum is σ = 131026238200. Its totient is φ = 131024164464.

The previous prime is 131025201323. The next prime is 131025201367. The reversal of 131025201331 is 133102520131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 131025201331 - 23 = 131025201323 is a prime.

It is a super-2 number, since 2×1310252013312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131025201301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297501 + ... + 592078.

It is an arithmetic number, because the mean of its divisors is an integer number (32756559550).

Almost surely, 2131025201331 is an apocalyptic number.

131025201331 is a deficient number, since it is larger than the sum of its proper divisors (1036869).

131025201331 is an equidigital number, since it uses as much as digits as its factorization.

131025201331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1036868.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 131025201331 its reverse (133102520131), we get a palindrome (264127721462).

The spelling of 131025201331 in words is "one hundred thirty-one billion, twenty-five million, two hundred one thousand, three hundred thirty-one".

Divisors: 1 147289 889579 131025201331