Base | Representation |
---|---|
bin | 10011000100010011111… |
… | …110101011001010100001 |
3 | 11122021010002000221200001 |
4 | 103010103332223022201 |
5 | 132431443324101423 |
6 | 2441535453100001 |
7 | 163444314056431 |
oct | 23042376531241 |
9 | 4567102027601 |
10 | 1310300222113 |
11 | 465771352553 |
12 | 191b40a87601 |
13 | 9673a05c81c |
14 | 475c153c2c1 |
15 | 2413d337cad |
hex | 13113fab2a1 |
1310300222113 has 4 divisors (see below), whose sum is σ = 1310316632320. Its totient is φ = 1310283811908.
The previous prime is 1310300222081. The next prime is 1310300222141. The reversal of 1310300222113 is 3112220030131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1310300222113 - 25 = 1310300222081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1310303222113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8084745 + ... + 8245222.
It is an arithmetic number, because the mean of its divisors is an integer number (327579158080).
Almost surely, 21310300222113 is an apocalyptic number.
It is an amenable number.
1310300222113 is a deficient number, since it is larger than the sum of its proper divisors (16410207).
1310300222113 is an equidigital number, since it uses as much as digits as its factorization.
1310300222113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16410206.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1310300222113 its reverse (3112220030131), we get a palindrome (4422520252244).
The spelling of 1310300222113 in words is "one trillion, three hundred ten billion, three hundred million, two hundred twenty-two thousand, one hundred thirteen".
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