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1310300222113 = 8023916329967
BaseRepresentation
bin10011000100010011111…
…110101011001010100001
311122021010002000221200001
4103010103332223022201
5132431443324101423
62441535453100001
7163444314056431
oct23042376531241
94567102027601
101310300222113
11465771352553
12191b40a87601
139673a05c81c
14475c153c2c1
152413d337cad
hex13113fab2a1

1310300222113 has 4 divisors (see below), whose sum is σ = 1310316632320. Its totient is φ = 1310283811908.

The previous prime is 1310300222081. The next prime is 1310300222141. The reversal of 1310300222113 is 3112220030131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310300222113 - 25 = 1310300222081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310303222113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8084745 + ... + 8245222.

It is an arithmetic number, because the mean of its divisors is an integer number (327579158080).

Almost surely, 21310300222113 is an apocalyptic number.

It is an amenable number.

1310300222113 is a deficient number, since it is larger than the sum of its proper divisors (16410207).

1310300222113 is an equidigital number, since it uses as much as digits as its factorization.

1310300222113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16410206.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1310300222113 its reverse (3112220030131), we get a palindrome (4422520252244).

The spelling of 1310300222113 in words is "one trillion, three hundred ten billion, three hundred million, two hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 80239 16329967 1310300222113