Base | Representation |
---|---|
bin | 111101000001000000… |
… | …0101000110100010011 |
3 | 110112012201111001110201 |
4 | 1322002000220310103 |
5 | 4121322214133042 |
6 | 140110000240031 |
7 | 12316023346204 |
oct | 1720200506423 |
9 | 415181431421 |
10 | 131030224147 |
11 | 5062a166849 |
12 | 21489910017 |
13 | c482464a14 |
14 | 64b02435ab |
15 | 361d5151b7 |
hex | 1e82028d13 |
131030224147 has 2 divisors, whose sum is σ = 131030224148. Its totient is φ = 131030224146.
The previous prime is 131030224109. The next prime is 131030224151. The reversal of 131030224147 is 741422030131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131030224147 - 27 = 131030224019 is a prime.
It is not a weakly prime, because it can be changed into another prime (131030224177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515112073 + 65515112074.
It is an arithmetic number, because the mean of its divisors is an integer number (65515112074).
Almost surely, 2131030224147 is an apocalyptic number.
131030224147 is a deficient number, since it is larger than the sum of its proper divisors (1).
131030224147 is an equidigital number, since it uses as much as digits as its factorization.
131030224147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 131030224147 its reverse (741422030131), we get a palindrome (872452254278).
The spelling of 131030224147 in words is "one hundred thirty-one billion, thirty million, two hundred twenty-four thousand, one hundred forty-seven".
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