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131031000313 = 139942669067
BaseRepresentation
bin111101000001000001…
…1100110010011111001
3110112012202221111011121
41322002003212103321
54121322414002223
6140110025025241
712316033061113
oct1720203462371
9415182844147
10131031000313
115062a646a04
122148a025221
13c4826770a5
1464b03a63b3
15361d61a15d
hex1e820e64f9

131031000313 has 4 divisors (see below), whose sum is σ = 131973669520. Its totient is φ = 130088331108.

The previous prime is 131031000301. The next prime is 131031000329. The reversal of 131031000313 is 313000130131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131031000313 - 229 = 130494129401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131031000613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 471334395 + ... + 471334672.

It is an arithmetic number, because the mean of its divisors is an integer number (32993417380).

Almost surely, 2131031000313 is an apocalyptic number.

It is an amenable number.

131031000313 is a deficient number, since it is larger than the sum of its proper divisors (942669207).

131031000313 is an equidigital number, since it uses as much as digits as its factorization.

131031000313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 942669206.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 131031000313 its reverse (313000130131), we get a palindrome (444031130444).

The spelling of 131031000313 in words is "one hundred thirty-one billion, thirty-one million, three hundred thirteen", and thus it is an aban number.

Divisors: 1 139 942669067 131031000313