Base | Representation |
---|---|
bin | 11000011010000000… |
… | …11001111101010001 |
3 | 1020211011211001120002 |
4 | 30031000121331101 |
5 | 203313344041032 |
6 | 10004113055345 |
7 | 642464420522 |
oct | 141500317521 |
9 | 36734731502 |
10 | 13103112017 |
11 | 5614401aa6 |
12 | 2658257555 |
13 | 130a864b28 |
14 | 8c432a849 |
15 | 51a51d862 |
hex | 30d019f51 |
13103112017 has 2 divisors, whose sum is σ = 13103112018. Its totient is φ = 13103112016.
The previous prime is 13103111951. The next prime is 13103112053. The reversal of 13103112017 is 71021130131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9859695616 + 3243416401 = 99296^2 + 56951^2 .
It is a cyclic number.
It is not a de Polignac number, because 13103112017 - 214 = 13103095633 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13103112017.
It is not a weakly prime, because it can be changed into another prime (13103112917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551556008 + 6551556009.
It is an arithmetic number, because the mean of its divisors is an integer number (6551556009).
Almost surely, 213103112017 is an apocalyptic number.
It is an amenable number.
13103112017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103112017 is an equidigital number, since it uses as much as digits as its factorization.
13103112017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 126, while the sum is 20.
Adding to 13103112017 its reverse (71021130131), we get a palindrome (84124242148).
The spelling of 13103112017 in words is "thirteen billion, one hundred three million, one hundred twelve thousand, seventeen".
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