Base | Representation |
---|---|
bin | 1011111010101100111011… |
… | …1000101111000010010111 |
3 | 1201101122110001021212221020 |
4 | 2332223032320233002113 |
5 | 3204140143013411043 |
6 | 43511254002252223 |
7 | 2521445362534614 |
oct | 276531670570227 |
9 | 51348401255836 |
10 | 13103121232023 |
11 | 41a2003379699 |
12 | 1577580957073 |
13 | 740808017cc4 |
14 | 3342a180950b |
15 | 17ac97910e83 |
hex | beacee2f097 |
13103121232023 has 16 divisors (see below), whose sum is σ = 17800591242240. Its totient is φ = 8570534997024.
The previous prime is 13103121231979. The next prime is 13103121232031. The reversal of 13103121232023 is 32023212130131.
It is not a de Polignac number, because 13103121232023 - 29 = 13103121231511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13103121231984 and 13103121232002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13103121232093) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 41051118 + ... + 41369076.
It is an arithmetic number, because the mean of its divisors is an integer number (1112536952640).
Almost surely, 213103121232023 is an apocalyptic number.
13103121232023 is a deficient number, since it is larger than the sum of its proper divisors (4697470010217).
13103121232023 is a wasteful number, since it uses less digits than its factorization.
13103121232023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 577198.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13103121232023 its reverse (32023212130131), we get a palindrome (45126333362154).
The spelling of 13103121232023 in words is "thirteen trillion, one hundred three billion, one hundred twenty-one million, two hundred thirty-two thousand, twenty-three".
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