Base | Representation |
---|---|
bin | 11101110010110000010110… |
… | …100001011010000001001100 |
3 | 122011221110112102020100210212 |
4 | 131302300112201122001030 |
5 | 114133303434432404234 |
6 | 1142402530512421552 |
7 | 36412460165132624 |
oct | 3562602641320114 |
9 | 564843472210725 |
10 | 131031240122444 |
11 | 38829045087532 |
12 | 128428952478b8 |
13 | 5816267b1777c |
14 | 244dd35625884 |
15 | 102365374c5ce |
hex | 772c1685a04c |
131031240122444 has 96 divisors (see below), whose sum is σ = 246675122400000. Its totient is φ = 60719488966656.
The previous prime is 131031240122411. The next prime is 131031240122449. The reversal of 131031240122444 is 444221042130131.
It is a super-2 number, since 2×1310312401224442 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131031240122444.
It is not an unprimeable number, because it can be changed into a prime (131031240122449) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 451112492 + ... + 451402860.
It is an arithmetic number, because the mean of its divisors is an integer number (2569532525000).
Almost surely, 2131031240122444 is an apocalyptic number.
It is an amenable number.
131031240122444 is a deficient number, since it is larger than the sum of its proper divisors (115643882277556).
131031240122444 is a wasteful number, since it uses less digits than its factorization.
131031240122444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 291127 (or 291125 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 131031240122444 its reverse (444221042130131), we get a palindrome (575252282252575).
The spelling of 131031240122444 in words is "one hundred thirty-one trillion, thirty-one billion, two hundred forty million, one hundred twenty-two thousand, four hundred forty-four".
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