Base | Representation |
---|---|
bin | 1011111010101100111110… |
… | …0110111001001010110011 |
3 | 1201101122110220001122011222 |
4 | 2332223033212321022303 |
5 | 3204140204113112042 |
6 | 43511255113455255 |
7 | 2521445600432135 |
oct | 276531746711263 |
9 | 51348426048158 |
10 | 13103133332147 |
11 | 41a200a1936a1 |
12 | 1577584a1152b |
13 | 74080a693741 |
14 | 3342a3279055 |
15 | 17ac98a012d2 |
hex | beacf9b92b3 |
13103133332147 has 2 divisors, whose sum is σ = 13103133332148. Its totient is φ = 13103133332146.
The previous prime is 13103133332123. The next prime is 13103133332209. The reversal of 13103133332147 is 74123333130131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13103133332147 - 214 = 13103133315763 is a prime.
It is not a weakly prime, because it can be changed into another prime (13103133332117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551566666073 + 6551566666074.
It is an arithmetic number, because the mean of its divisors is an integer number (6551566666074).
Almost surely, 213103133332147 is an apocalyptic number.
13103133332147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103133332147 is an equidigital number, since it uses as much as digits as its factorization.
13103133332147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824, while the sum is 35.
Adding to 13103133332147 its reverse (74123333130131), we get a palindrome (87226466462278).
The spelling of 13103133332147 in words is "thirteen trillion, one hundred three billion, one hundred thirty-three million, three hundred thirty-two thousand, one hundred forty-seven".
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