131032032440314 has 4 divisors (see below), whose sum is σ = 196548048660474. Its totient is φ = 65516016220156.

The previous prime is 131032032440311. The next prime is 131032032440333. The reversal of 131032032440314 is 413044230230131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 129976348114089 + 1055684326225 = 11400717^2 + 1027465^2 .

It is not an unprimeable number, because it can be changed into a prime (131032032440311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32758008110077 + ... + 32758008110080.

Almost surely, 2^{131032032440314} is an apocalyptic number.

131032032440314 is a deficient number, since it is larger than the sum of its proper divisors (65516016220160).

131032032440314 is an equidigital number, since it uses as much as digits as its factorization.

131032032440314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65516016220159.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 131032032440314 its reverse (413044230230131), we get a palindrome (544076262670445).

The spelling of 131032032440314 in words is "one hundred thirty-one trillion, thirty-two billion, thirty-two million, four hundred forty thousand, three hundred fourteen".