Base | Representation |
---|---|
bin | 1011111010101110000111… |
… | …1110101000000101101011 |
3 | 1201101200021101000101201102 |
4 | 2332223201332220011223 |
5 | 3204141322013343111 |
6 | 43511345443512015 |
7 | 2521456332251453 |
oct | 276534176500553 |
9 | 51350241011642 |
10 | 13103441543531 |
11 | 41a2158166449 |
12 | 157765008860b |
13 | 7408594a7c41 |
14 | 3342d2188d63 |
15 | 17acb5ad313b |
hex | beae1fa816b |
13103441543531 has 2 divisors, whose sum is σ = 13103441543532. Its totient is φ = 13103441543530.
The previous prime is 13103441543477. The next prime is 13103441543557. The reversal of 13103441543531 is 13534514430131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13103441543531 - 222 = 13103437349227 is a prime.
It is a super-2 number, since 2×131034415435312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13103441543831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551720771765 + 6551720771766.
It is an arithmetic number, because the mean of its divisors is an integer number (6551720771766).
Almost surely, 213103441543531 is an apocalyptic number.
13103441543531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13103441543531 is an equidigital number, since it uses as much as digits as its factorization.
13103441543531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 38.
Adding to 13103441543531 its reverse (13534514430131), we get a palindrome (26637955973662).
The spelling of 13103441543531 in words is "thirteen trillion, one hundred three billion, four hundred forty-one million, five hundred forty-three thousand, five hundred thirty-one".
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