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1310344243042 = 2655172121521
BaseRepresentation
bin10011000100010110100…
…110100110011101100010
311122021020010212110000211
4103010112212212131202
5132432041111234132
62441544104404334
7163445360202352
oct23042646463542
94567203773024
101310344243042
1146579418a08a
12191b537766aa
1396746203603
14475c731ab62
1524142131147
hex131169a6762

1310344243042 has 4 divisors (see below), whose sum is σ = 1965516364566. Its totient is φ = 655172121520.

The previous prime is 1310344243037. The next prime is 1310344243129. The reversal of 1310344243042 is 2403424430131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 844099725001 + 466244518041 = 918749^2 + 682821^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1310344242995 and 1310344243013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327586060759 + ... + 327586060762.

Almost surely, 21310344243042 is an apocalyptic number.

1310344243042 is a deficient number, since it is larger than the sum of its proper divisors (655172121524).

1310344243042 is an equidigital number, since it uses as much as digits as its factorization.

1310344243042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655172121523.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1310344243042 its reverse (2403424430131), we get a palindrome (3713768673173).

The spelling of 1310344243042 in words is "one trillion, three hundred ten billion, three hundred forty-four million, two hundred forty-three thousand, forty-two".

Divisors: 1 2 655172121521 1310344243042