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13103973191347 is a prime number
BaseRepresentation
bin1011111010110000000110…
…1010101100111010110011
31201101201122102101220102021
42332230001222230322303
53204143414114110342
643511514314532311
72521505446216213
oct276540152547263
951351572356367
1013103973191347
1141a2400279305
12157777a137097
1374091269104c
14334342a1c243
1517ace75ed567
hexbeb01aaceb3

13103973191347 has 2 divisors, whose sum is σ = 13103973191348. Its totient is φ = 13103973191346.

The previous prime is 13103973191333. The next prime is 13103973191357. The reversal of 13103973191347 is 74319137930131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13103973191347 - 211 = 13103973189299 is a prime.

It is a super-2 number, since 2×131039731913472 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13103973191294 and 13103973191303.

It is not a weakly prime, because it can be changed into another prime (13103973191357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551986595673 + 6551986595674.

It is an arithmetic number, because the mean of its divisors is an integer number (6551986595674).

Almost surely, 213103973191347 is an apocalyptic number.

13103973191347 is a deficient number, since it is larger than the sum of its proper divisors (1).

13103973191347 is an equidigital number, since it uses as much as digits as its factorization.

13103973191347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1285956, while the sum is 52.

The spelling of 13103973191347 in words is "thirteen trillion, one hundred three billion, nine hundred seventy-three million, one hundred ninety-one thousand, three hundred forty-seven".