Base | Representation |
---|---|
bin | 10011000100011001111… |
… | …100000100001000010001 |
3 | 11122021101001011102020102 |
4 | 103010121330010020101 |
5 | 132432144422414413 |
6 | 2441553424022145 |
7 | 163446636633644 |
oct | 23043174041021 |
9 | 4567331142212 |
10 | 1310400201233 |
11 | 46581282a322 |
12 | 191b6a461955 |
13 | 96754996976 |
14 | 475d0925a5b |
15 | 24146ed6458 |
hex | 13119f04211 |
1310400201233 has 2 divisors, whose sum is σ = 1310400201234. Its totient is φ = 1310400201232.
The previous prime is 1310400201211. The next prime is 1310400201241. The reversal of 1310400201233 is 3321020040131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1309999280704 + 400920529 = 1144552^2 + 20023^2 .
It is an emirp because it is prime and its reverse (3321020040131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1310400201233 - 224 = 1310383424017 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310400201133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655200100616 + 655200100617.
It is an arithmetic number, because the mean of its divisors is an integer number (655200100617).
Almost surely, 21310400201233 is an apocalyptic number.
It is an amenable number.
1310400201233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310400201233 is an equidigital number, since it uses as much as digits as its factorization.
1310400201233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1310400201233 its reverse (3321020040131), we get a palindrome (4631420241364).
The spelling of 1310400201233 in words is "one trillion, three hundred ten billion, four hundred million, two hundred one thousand, two hundred thirty-three".
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