Base | Representation |
---|---|
bin | 10011000100011010000… |
… | …111001011000111001001 |
3 | 11122021101020122101000002 |
4 | 103010122013023013021 |
5 | 132432201144112132 |
6 | 2441554010252345 |
7 | 163450003453166 |
oct | 23043207130711 |
9 | 4567336571002 |
10 | 1310403113417 |
11 | 465814439292 |
12 | 191b6b4270b5 |
13 | 96755476358 |
14 | 475d108306d |
15 | 241473ae262 |
hex | 1311a1cb1c9 |
1310403113417 has 2 divisors, whose sum is σ = 1310403113418. Its totient is φ = 1310403113416.
The previous prime is 1310403113303. The next prime is 1310403113447. The reversal of 1310403113417 is 7143113040131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 784634553616 + 525768559801 = 885796^2 + 725099^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310403113417 - 210 = 1310403112393 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1310403113417.
It is not a weakly prime, because it can be changed into another prime (1310403113447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655201556708 + 655201556709.
It is an arithmetic number, because the mean of its divisors is an integer number (655201556709).
Almost surely, 21310403113417 is an apocalyptic number.
It is an amenable number.
1310403113417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310403113417 is an equidigital number, since it uses as much as digits as its factorization.
1310403113417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 1310403113417 its reverse (7143113040131), we get a palindrome (8453516153548).
The spelling of 1310403113417 in words is "one trillion, three hundred ten billion, four hundred three million, one hundred thirteen thousand, four hundred seventeen".
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