Base | Representation |
---|---|
bin | 1111100111110… |
… | …00010010110001 |
3 | 100010120112200101 |
4 | 13303320102301 |
5 | 232021243213 |
6 | 21000352401 |
7 | 3150553036 |
oct | 763702261 |
9 | 303515611 |
10 | 131040433 |
11 | 67a72687 |
12 | 37a75701 |
13 | 211c1224 |
14 | 1359138d |
15 | b786bdd |
hex | 7cf84b1 |
131040433 has 4 divisors (see below), whose sum is σ = 133512948. Its totient is φ = 128567920.
The previous prime is 131040389. The next prime is 131040457. The reversal of 131040433 is 334040131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 70946929 + 60093504 = 8423^2 + 7752^2 .
It is a cyclic number.
It is not a de Polignac number, because 131040433 - 221 = 128943281 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131040433.
It is not an unprimeable number, because it can be changed into a prime (131020433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1236178 + ... + 1236283.
It is an arithmetic number, because the mean of its divisors is an integer number (33378237).
Almost surely, 2131040433 is an apocalyptic number.
It is an amenable number.
131040433 is a deficient number, since it is larger than the sum of its proper divisors (2472515).
131040433 is an equidigital number, since it uses as much as digits as its factorization.
131040433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2472514.
The product of its (nonzero) digits is 432, while the sum is 19.
The square root of 131040433 is about 11447.2893297933. The cubic root of 131040433 is about 507.9275541491.
Adding to 131040433 its reverse (334040131), we get a palindrome (465080564).
The spelling of 131040433 in words is "one hundred thirty-one million, forty thousand, four hundred thirty-three".
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