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13104103210441 = 28355783131511
BaseRepresentation
bin1011111010110000100101…
…1010101011110111001001
31201101201222111001120002021
42332230021122223313021
53204144200410213231
643511535241404441
72521511615316505
oct276541132536711
951351874046067
1013104103210441
1141a2467703601
1215777b5799721
137409335b5419
14334355dc5305
1517ad03c32811
hexbeb096abdc9

13104103210441 has 8 divisors (see below), whose sum is σ = 13174016969664. Its totient is φ = 13034355715920.

The previous prime is 13104103210423. The next prime is 13104103210567. The reversal of 13104103210441 is 14401230140131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13104103210441 - 25 = 13104103210409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104103216441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41408125 + ... + 41723386.

It is an arithmetic number, because the mean of its divisors is an integer number (1646752121208).

Almost surely, 213104103210441 is an apocalyptic number.

It is an amenable number.

13104103210441 is a deficient number, since it is larger than the sum of its proper divisors (69913759223).

13104103210441 is an equidigital number, since it uses as much as digits as its factorization.

13104103210441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83132351.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13104103210441 its reverse (14401230140131), we get a palindrome (27505333350572).

The spelling of 13104103210441 in words is "thirteen trillion, one hundred four billion, one hundred three million, two hundred ten thousand, four hundred forty-one".

Divisors: 1 283 557 157631 83131511 23526217613 46304251627 13104103210441