Base | Representation |
---|---|
bin | 1011111010110000100101… |
… | …1101110001100001001010 |
3 | 1201101201222112120200122111 |
4 | 2332230021131301201022 |
5 | 3204144201112120132 |
6 | 43511535311012534 |
7 | 2521511625231040 |
oct | 276541135614112 |
9 | 51351875520574 |
10 | 13104104020042 |
11 | 41a24681068a2 |
12 | 15777b5b0a14a |
13 | 740933809a89 |
14 | 334356156390 |
15 | 17ad03d42647 |
hex | beb0977184a |
13104104020042 has 16 divisors (see below), whose sum is σ = 22467984014592. Its totient is φ = 5615093156400.
The previous prime is 13104104020003. The next prime is 13104104020043. The reversal of 13104104020042 is 24002040140131.
It is a happy number.
13104104020042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13104104019995 and 13104104020022.
It is not an unprimeable number, because it can be changed into a prime (13104104020043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79199709 + ... + 79364992.
It is an arithmetic number, because the mean of its divisors is an integer number (1404249000912).
Almost surely, 213104104020042 is an apocalyptic number.
13104104020042 is a deficient number, since it is larger than the sum of its proper divisors (9363879994550).
13104104020042 is a wasteful number, since it uses less digits than its factorization.
13104104020042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158570613.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 13104104020042 its reverse (24002040140131), we get a palindrome (37106144160173).
The spelling of 13104104020042 in words is "thirteen trillion, one hundred four billion, one hundred four million, twenty thousand, forty-two".
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