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13104104121000 = 2332534007363367
BaseRepresentation
bin1011111010110000100101…
…1110001010001010101000
31201101201222112202211010200
42332230021132022022220
53204144201123333000
643511535313112200
72521511626131264
oct276541136121250
951351875684120
1013104104121000
1141a2468175732
1215777b5b58660
13740933843a09
143343561810a4
1517ad03d62500
hexbeb0978a2a8

13104104121000 has 192 divisors, whose sum is σ = 44303047476480. Its totient is φ = 3493546070400.

The previous prime is 13104104120981. The next prime is 13104104121041. The reversal of 13104104121000 is 12140140131.

13104104121000 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 410 + 41 + 210 + 0 + 0 = 666.

It is a super-3 number, since 3×131041041210003 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 35881317 + ... + 36244683.

It is an arithmetic number, because the mean of its divisors is an integer number (230745038940).

Almost surely, 213104104121000 is an apocalyptic number.

13104104121000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13104104121000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22151523738240).

13104104121000 is an abundant number, since it is smaller than the sum of its proper divisors (31198943355480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104104121000 is a wasteful number, since it uses less digits than its factorization.

13104104121000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 367401 (or 367384 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 13104104121000 its reverse (12140140131), we get a palindrome (13116244261131).

The spelling of 13104104121000 in words is "thirteen trillion, one hundred four billion, one hundred four million, one hundred twenty-one thousand".