Base | Representation |
---|---|
bin | 10011000100011011001… |
… | …011001110001010011011 |
3 | 11122021102111012122112111 |
4 | 103010123023032022123 |
5 | 132432220230423312 |
6 | 2441555444453151 |
7 | 163450311206650 |
oct | 23043313161233 |
9 | 4567374178474 |
10 | 1310420951707 |
11 | 46582351247a |
12 | 191b753aa1b7 |
13 | 9675908085a |
14 | 475d35a7c27 |
15 | 24148c348a7 |
hex | 1311b2ce29b |
1310420951707 has 16 divisors (see below), whose sum is σ = 1534531428864. Its totient is φ = 1095550920000.
The previous prime is 1310420951641. The next prime is 1310420951711. The reversal of 1310420951707 is 7071590240131.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1310420951707 - 211 = 1310420949659 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1310420951707.
It is not an unprimeable number, because it can be changed into a prime (1310420951737) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 599082 + ... + 1726192.
It is an arithmetic number, because the mean of its divisors is an integer number (95908214304).
Almost surely, 21310420951707 is an apocalyptic number.
1310420951707 is a deficient number, since it is larger than the sum of its proper divisors (224110477157).
1310420951707 is a wasteful number, since it uses less digits than its factorization.
1310420951707 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1131210.
The product of its (nonzero) digits is 52920, while the sum is 40.
The spelling of 1310420951707 in words is "one trillion, three hundred ten billion, four hundred twenty million, nine hundred fifty-one thousand, seven hundred seven".
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