13104230112321 has 4 divisors (see below), whose sum is σ = 17472306816432. Its totient is φ = 8736153408212.

The previous prime is 13104230112287. The next prime is 13104230112341. The reversal of 13104230112321 is 12321103240131.

13104230112321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104230112321 - 2⁹ = 13104230111809 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104230112291 and 13104230112300.

It is not an unprimeable number, because it can be changed into a prime (13104230112341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2184038352051 + ... + 2184038352056.

It is an arithmetic number, because the mean of its divisors is an integer number (4368076704108).

Almost surely, 2^{13104230112321} is an apocalyptic number.

It is an amenable number.

13104230112321 is a deficient number, since it is larger than the sum of its proper divisors (4368076704111).

13104230112321 is an equidigital number, since it uses as much as digits as its factorization.

13104230112321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4368076704110.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 13104230112321 its reverse (12321103240131), we get a palindrome (25425333352452).

The spelling of 13104230112321 in words is "thirteen trillion, one hundred four billion, two hundred thirty million, one hundred twelve thousand, three hundred twenty-one".