Base | Representation |
---|---|
bin | 10011000100011011010… |
… | …111101010101110101001 |
3 | 11122021102201100102011111 |
4 | 103010123113222232221 |
5 | 132432222044330231 |
6 | 2442000042430321 |
7 | 163450351016206 |
oct | 23043327525651 |
9 | 4567381312144 |
10 | 1310424214441 |
11 | 465825340851 |
12 | 191b765023a1 |
13 | 96759953974 |
14 | 475d3bb6cad |
15 | 2414917b4b1 |
hex | 1311b5eaba9 |
1310424214441 has 4 divisors (see below), whose sum is σ = 1310428590084. Its totient is φ = 1310419838800.
The previous prime is 1310424214339. The next prime is 1310424214453. The reversal of 1310424214441 is 1444124240131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 952585760025 + 357838454416 = 976005^2 + 598196^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310424214441 - 211 = 1310424212393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1310424214471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1702750 + ... + 2349511.
It is an arithmetic number, because the mean of its divisors is an integer number (327607147521).
Almost surely, 21310424214441 is an apocalyptic number.
It is an amenable number.
1310424214441 is a deficient number, since it is larger than the sum of its proper divisors (4375643).
1310424214441 is an equidigital number, since it uses as much as digits as its factorization.
1310424214441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4375642.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 1310424214441 its reverse (1444124240131), we get a palindrome (2754548454572).
The spelling of 1310424214441 in words is "one trillion, three hundred ten billion, four hundred twenty-four million, two hundred fourteen thousand, four hundred forty-one".
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