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13104273355489 = 71184567230359
BaseRepresentation
bin1011111010110001001110…
…0011101111001011100001
31201101202102100012211012201
42332230103203233023201
53204200022434333424
643512004200253201
72521516052451301
oct276542343571341
951352370184181
1013104273355489
1141a2544755048
121577842771201
1374095c918774
14334370835601
1517ad13b40d44
hexbeb138ef2e1

13104273355489 has 4 divisors (see below), whose sum is σ = 13288840585920. Its totient is φ = 12919706125060.

The previous prime is 13104273355487. The next prime is 13104273355501. The reversal of 13104273355489 is 98455337240131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104273355489 - 21 = 13104273355487 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104273355487) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92283615109 + ... + 92283615250.

It is an arithmetic number, because the mean of its divisors is an integer number (3322210146480).

Almost surely, 213104273355489 is an apocalyptic number.

It is an amenable number.

13104273355489 is a deficient number, since it is larger than the sum of its proper divisors (184567230431).

13104273355489 is an equidigital number, since it uses as much as digits as its factorization.

13104273355489 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 184567230430.

The product of its (nonzero) digits is 10886400, while the sum is 55.

The spelling of 13104273355489 in words is "thirteen trillion, one hundred four billion, two hundred seventy-three million, three hundred fifty-five thousand, four hundred eighty-nine".

Divisors: 1 71 184567230359 13104273355489