Base | Representation |
---|---|
bin | 111101000001011000… |
… | …1011111010110101001 |
3 | 110112020121120200101220 |
4 | 1322002301133112221 |
5 | 4121334003433231 |
6 | 140111134532253 |
7 | 12316240244301 |
oct | 1720261372651 |
9 | 415217520356 |
10 | 131043030441 |
11 | 50636413364 |
12 | 21492067089 |
13 | c484cc99cb |
14 | 64b1c18601 |
15 | 361e6e4896 |
hex | 1e82c5f5a9 |
131043030441 has 4 divisors (see below), whose sum is σ = 174724040592. Its totient is φ = 87362020292.
The previous prime is 131043030421. The next prime is 131043030463. The reversal of 131043030441 is 144030340131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131043030441 - 25 = 131043030409 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131043030421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21840505071 + ... + 21840505076.
It is an arithmetic number, because the mean of its divisors is an integer number (43681010148).
Almost surely, 2131043030441 is an apocalyptic number.
It is an amenable number.
131043030441 is a deficient number, since it is larger than the sum of its proper divisors (43681010151).
131043030441 is an equidigital number, since it uses as much as digits as its factorization.
131043030441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43681010150.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 131043030441 its reverse (144030340131), we get a palindrome (275073370572).
The spelling of 131043030441 in words is "one hundred thirty-one billion, forty-three million, thirty thousand, four hundred forty-one".
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