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131043214023419 is a prime number
BaseRepresentation
bin11101110010111011100000…
…001110001101101011111011
3122011222121102220020120000202
4131302323200032031223323
5114134003000242222134
61142412231010552415
736413363001456125
oct3562734016155373
9564877386216022
10131043214023419
113883312a032565
121284507729870b
135817425741a89
14245074d9ac215
151023b04a64d7e
hex772ee038dafb

131043214023419 has 2 divisors, whose sum is σ = 131043214023420. Its totient is φ = 131043214023418.

The previous prime is 131043214023409. The next prime is 131043214023487. The reversal of 131043214023419 is 914320412340131.

It is a weak prime.

It is an emirp because it is prime and its reverse (914320412340131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131043214023419 is a prime.

It is a super-2 number, since 2×1310432140234192 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131043214023409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521607011709 + 65521607011710.

It is an arithmetic number, because the mean of its divisors is an integer number (65521607011710).

Almost surely, 2131043214023419 is an apocalyptic number.

131043214023419 is a deficient number, since it is larger than the sum of its proper divisors (1).

131043214023419 is an equidigital number, since it uses as much as digits as its factorization.

131043214023419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 38.

The spelling of 131043214023419 in words is "one hundred thirty-one trillion, forty-three billion, two hundred fourteen million, twenty-three thousand, four hundred nineteen".