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131043214027211 is a prime number
BaseRepresentation
bin11101110010111011100000…
…001110001110100111001011
3122011222121102220020202020012
4131302323200032032213023
5114134003000242332321
61142412231011022135
736413363001503153
oct3562734016164713
9564877386222205
10131043214027211
113883312a0353a2
121284507729a94b
135817425743715
14245074d9ad763
151023b04a6605b
hex772ee038e9cb

131043214027211 has 2 divisors, whose sum is σ = 131043214027212. Its totient is φ = 131043214027210.

The previous prime is 131043214027171. The next prime is 131043214027217. The reversal of 131043214027211 is 112720412340131.

It is a strong prime.

It is an emirp because it is prime and its reverse (112720412340131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131043214027211 - 226 = 131043146918347 is a prime.

It is not a weakly prime, because it can be changed into another prime (131043214027217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521607013605 + 65521607013606.

It is an arithmetic number, because the mean of its divisors is an integer number (65521607013606).

Almost surely, 2131043214027211 is an apocalyptic number.

131043214027211 is a deficient number, since it is larger than the sum of its proper divisors (1).

131043214027211 is an equidigital number, since it uses as much as digits as its factorization.

131043214027211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 32.

Adding to 131043214027211 its reverse (112720412340131), we get a palindrome (243763626367342).

The spelling of 131043214027211 in words is "one hundred thirty-one trillion, forty-three billion, two hundred fourteen million, twenty-seven thousand, two hundred eleven".