Base | Representation |
---|---|
bin | 11101110010111011100000… |
… | …001110001110100111001011 |
3 | 122011222121102220020202020012 |
4 | 131302323200032032213023 |
5 | 114134003000242332321 |
6 | 1142412231011022135 |
7 | 36413363001503153 |
oct | 3562734016164713 |
9 | 564877386222205 |
10 | 131043214027211 |
11 | 3883312a0353a2 |
12 | 1284507729a94b |
13 | 5817425743715 |
14 | 245074d9ad763 |
15 | 1023b04a6605b |
hex | 772ee038e9cb |
131043214027211 has 2 divisors, whose sum is σ = 131043214027212. Its totient is φ = 131043214027210.
The previous prime is 131043214027171. The next prime is 131043214027217. The reversal of 131043214027211 is 112720412340131.
It is a strong prime.
It is an emirp because it is prime and its reverse (112720412340131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131043214027211 - 226 = 131043146918347 is a prime.
It is not a weakly prime, because it can be changed into another prime (131043214027217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521607013605 + 65521607013606.
It is an arithmetic number, because the mean of its divisors is an integer number (65521607013606).
Almost surely, 2131043214027211 is an apocalyptic number.
131043214027211 is a deficient number, since it is larger than the sum of its proper divisors (1).
131043214027211 is an equidigital number, since it uses as much as digits as its factorization.
131043214027211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 131043214027211 its reverse (112720412340131), we get a palindrome (243763626367342).
The spelling of 131043214027211 in words is "one hundred thirty-one trillion, forty-three billion, two hundred fourteen million, twenty-seven thousand, two hundred eleven".
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